Angular Velocity
Interactive Concept Module · JEE Main / NEET
Voice narration will guide you through each screen.
Angular Velocity · Interactive Concept Module Screen 1 of 8
Screen 01 · Concept of Angular Displacement
Concept Panel

Angular Displacement (θ)

Angle swept by the radius vector of a particle in circular motion, measured from a reference line.

radian (SI) degree
θ (rad) = arc length / radius  ·  180° = π rad
Interactive Canvas
↻ drag radius to rotate
θ = 0.00 rad
θ = 0.0°
Screen 02 · Defining Angular Velocity
Definitions

Average Angular Velocity

ω̄ = Δθ / Δt

Total angular displacement divided by total time interval.

Instantaneous Angular Velocity

ω = dθ / dt

Limit of average angular velocity as Δt → 0.

rad/s rev/min deg/s
Interactive Canvas
Δθ = 1.57 rad
Δt = 0.50 s
ω = 3.14 rad/s
Interactive
  • Slider: change Δθ and Δt
  • Observe ω update in real time
Controls
current: 1.57 rad
current: 0.50 s
Screen 03 · Direction of Angular Velocity
Concept Panel

Right-Hand Thumb Rule

Curl the fingers of your right hand in the direction of rotation. The thumb points along the direction of ω⃗.

↺ Anticlockwise
↻ Clockwise
⊙ out of screen→ anticlockwise ω
⊗ into screen→ clockwise ω
Interactive Canvas
ω⃗ (out of screen)
View
Screen 04 · Relation Between Linear & Angular Velocity
Key Relation

Linear ↔ Angular

v = r ω

v = linear (tangential) speed

r = radius (distance from axis)

ω = angular speed (rad/s)

Insight
All points on a rigid rotating body share the same ω, but points farther from the axis have larger linear speed v.
Interactive Canvas
Same ω · Different r
Interactive
  • Drag points to change r₁, r₂
  • Slider sets shared ω
  • v₁ and v₂ compared live
Controls
ω = 4.0 rad/s
r₁ = 0.20 m
r₂ = 0.45 m
v₁ (r₁ = 0.20 m) = 0.80 m/s
v₂ (r₂ = 0.45 m) = 1.80 m/s
v₁/v₂ = r₁/r₂ = 0.44
Screen 05 · Multiple Representations
MOTION ANIMATION
Challenge A · Motion → Graph

Watch the rotation. Pick the matching θ–t graph.

A
B
C
D
Challenge B · Motion → Graph

Watch the rotation above. Pick the matching ω–t graph.

A
B
C
D
Screen 06 · JEE Main Practice — Angular Velocity
Question

Q1.

A particle moves in a circle of radius 0.5 m with a constant angular speed. It completes 30 revolutions per minute. The linear speed of the particle is approximately:

Figure: particle on a horizontal circle, radius r = 0.5 m
Screen 07 · JEE Main Practice — Angular Velocity
Question

Q2.

The angular position of a rotating disc is given by θ(t) = 2t³ − 3t² + 4 (in radians, t in seconds). The angular velocity of the disc at t = 2 s is:

θ(t) = 2t³ − 3t² + 4
💡 Hint: ω = dθ/dt